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(3x-2)^1/2=4-x
We move all terms to the left:
(3x-2)^1/2-(4-x)=0
We add all the numbers together, and all the variables
(3x-2)^1/2-(-1x+4)=0
We get rid of parentheses
(3x-2)^1/2+1x-4=0
We multiply all the terms by the denominator
(3x-2)^1+1x*2-4*2=0
We add all the numbers together, and all the variables
(3x-2)^1+1x*2-8=0
Wy multiply elements
(3x-2)^1+2x-8=0
We add all the numbers together, and all the variables
2x+(3x-2)^1-8=0
We move all terms containing x to the left, all other terms to the right
2x+(3x-2)^1=8
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